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Ideas for Teaching

Why Radar Can't (Usually) See Tornadoes

Page 1 | Page 2 | Page 3 | Page 4

Beamwidth Size vs. Object Size

Beamwidth

What can a radar see? Beamwidth is one consideration. Earth curvature and height of the feature is another (addressed on the next page). We'll soon understand why researchers built mobile radars...

For the moment, we'll keep the problem in two dimensions and ignore height above ground. The geometry is an isoceles triangle. Be sure to note which beamwidth you are calculating for (i.e. 1 degree).

Distance from radar Width of the "beam"
20 mi  
40 mi  
60 mi  
80 mi  

Diagram of geometry for this problem

Object Size

How wide and tall are various things we want to see?

Width of Meteorological Objects (i.e. Storms, Tornadoes)
Object Width Height or Depth
Supercell thunderstorm 10-30 mi 28,000-55,000 ft
Circulation within the supercell thunderstorm 2-8 mi 2,000-55,000 ft
Tornado 0.1 - 1.0 mi Cloud base - 0.5 - 1.5 mi*
Individual storm cell within a squall line 2-8 mi 4,000-55,000 ft
Circulation embedded within a squall line 2-5 mi 4,000-40,000 ft

How Many Data Points?

As you consider the numbers you've calculated, also consider how many data points you'd like to have to detect the supercell thunderstorm, tornado, etc. Is one point enough? Probably not, especially if you want to see motion within a circulation.

Mobile radars

Now can you see why scientists put radars onto trucks? What kind of resolution can they gain by driving up near to the storm? Consider making another table with several distances ranging from 10-50 mi.

On to page 4 and earth curvature...

*How tall is a tornado? Good question. I noted cloud base because that is visually the "top" of a tornado. However, a true supercell tornado circulation will go right up through the center of the mesocyclone, and that can be anywhere from a few thousand feet to the entire depth of the storm.

 

Last updated: March 28, 2002
Created by: DSZ